Floating point math issues
Revision as of 14:11, 9 April 2008 by Bmy
- Thank you to all that offered their suggestions for a "safe division" routine to prevent overflow. For those that are curious about the solution to the problem, I found useful to adopt a subroutine along the lines suggested by William Long:
if(exponent(a) - exponent (b) >= maxexponent(a) .OR. b==0)Then q=altv else q=a/b endif
- The = in the >= is to take into account the case when the fractional part of a is 1.111... and that of b is 1.
- It works very well.
- Thank you again,